(P∨Q)∧P⇔P
論理積と論理和で成り立つ吸収法則
証明
∧除去から直ちに導ける
https://scrapbox.io/files/68aebd5d76fb6820ac24e6cc.svg
逆は∧導入を使う
https://scrapbox.io/files/68aebdc4d36a31a7932d1bd5.svg
code:l2r.tikz(tex)
\usepackage{fitch}
\usepackage{amsmath}
\begin{document}
$\Large\begin{nd}
\hypo {l} {(P\lor Q)\land P}
\have {r} {P} \ae{l}
\end{nd}$
\end{document}
code:r2l.tikz(tex)
\usepackage{fitch}
\usepackage{amsmath}
\begin{document}
$\Large\begin{nd}
\hypo {r} {P}
\have {pq} {P\lor Q} \oi{r}
\have {l} {(P\lor Q)\land P} \ai{r,pq}
\end{nd}$
\end{document}
#2025-08-27 17:11:57
#2021-07-01 16:16:38