減算

$ \textrm{R}_1-\textrm{R}_2

https://gyazo.com/65237ae30168eb3451a5af816aceb9cb

(厳密には以下の式になります)

$ \textrm{Y}=\textup{max}(\textrm{Y}_1-\textrm{Y}_2, 0)

$ \textrm{Cb}=\begin{cases}{\textrm{Cb}_1-\textrm{Cb}_2\quad\small{(0\lt\textrm{Y}_1-\textrm{Y}_2)}}\\{(\textrm{Cb}_1-\textrm{Cb}_2)(1+4(\textrm{Y}_1-\textrm{Y}_2))\quad\small{(-0.25\lt\textrm{Y}_1-\textrm{Y}_2\le0)}}\\{0\quad\small{(\textrm{Y}_1-\textrm{Y}_2\le-0.25)}}\end{cases}

$ \textrm{Cr}=\begin{cases}{\textrm{Cr}_1-\textrm{Cr}_2\quad\small{(0\lt\textrm{Y}_1-\textrm{Y}_2)}}\\{(\textrm{Cr}_1-\textrm{Cr}_2)(1+4(\textrm{Y}_1-\textrm{Y}_2))\quad\small{(-0.25\lt\textrm{Y}_1-\textrm{Y}_2\le0)}}\\{0\quad\small{(\textrm{Y}_1-\textrm{Y}_2\le-0.25)}}\end{cases}