剰余演算

modulo operation; mod

$ \bmod

剰余によって数を特徴づける

$ 1000 \equiv -1 \pmod 7

$ 1000 \equiv -1 \mod 11

$ 1000 \equiv -1 \pod{13}

符号は除数に合わせられる

The result will have the same sign as y, and magnitude less than abs(y)

code:jl

mod.(-3:3, 3) # 0 1 2 0 1 2 0

mod.(-3:3, -3) # 0 -2 -1 0 -2 -1 0