Xenopus ruwenzoriensis (frog, 12n=108): Du Pasquier et al. (2009)
Du Pasquier et al. Frontiers in Bioscience (2009)
The fate of duplicated immunity genes in the dodecaploid Xenopus ruwenzoriensis
https://gyazo.com/6f62a25416e35ede64608e846499726d
https://gyazo.com/bd9889cd039dc09bf6b31b92508666d4
mitosis
chromosome
number
polyploidy
Xenopus ruwenzoriensis has 12n=108 chromosomes.
"In summary one can anticipate certain contradictory forces affecting the different immune genes in these species. In the case of antibody genes the question is “will all variable germline elements be expressed in a species having three times more genes but 40 times less cells?” as the situation is when comparing X. laevis (4n) and X. ruwenzoriensis (12n)” Perhaps the cell numbers in X. ruwenzoriensis lymphocyte clones will be too small to allow a given specificity to be efficient."
My Questions
How can cells have 12 pairs of homolog chromosomes finish meiotic recombination? There are 12 pairs of homolog chromosomes and its variation of combination of one pairs chosen from 12 pairs are so many. And then they have to recombine between only one pair (not over 2).